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29x^2+7x-36=0
a = 29; b = 7; c = -36;
Δ = b2-4ac
Δ = 72-4·29·(-36)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-65}{2*29}=\frac{-72}{58} =-1+7/29 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+65}{2*29}=\frac{58}{58} =1 $
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